what is the solution to the inequality? 3(x - 2) + x ≤ 2 enter your answer in the box.

Explanation:

Step1: Expand the left - hand side

$3(x - 2)+x=3x-6 + x=4x-6$. So the inequality becomes $4x-6\leq2$.

Step2: Add 6 to both sides

$4x-6 + 6\leq2 + 6$, which simplifies to $4x\leq8$.

Step3: Divide both sides by 4

$\frac{4x}{4}\leq\frac{8}{4}$, so $x\leq2$.

Answer:

$x\leq2$