what is the solution to the linear equation?\nd - 10 - 2d + 7 = 8 + d - 10 - 3d\no d = -5\no d = -1\no d =…

Answer:

C. $d = 1$

Explanation:

Step1: Combine like - terms on both sides

Left - hand side: $d-2d-10 + 7=-d - 3$. Right - hand side: $d-3d+8 - 10=-2d - 2$. So the equation becomes $-d - 3=-2d - 2$.

Step2: Add $2d$ to both sides

$-d+2d - 3=-2d+2d - 2$, which simplifies to $d - 3=-2$.

Step3: Add 3 to both sides

$d-3 + 3=-2 + 3$, so $d = 1$.