what is the solution to the linear equation? -12 + 3b - 1 = -5 - b\no b = -2\no b = -1.5\no b = 1.5\no b = 2

Explanation:

Step1: Combine like - terms on left side

Combine $-12$ and $-1$ in the equation $-12 + 3b-1=-5 - b$. $-13 + 3b=-5 - b$

Step2: Add $b$ to both sides

To get all $b$ terms on one side. $-13 + 3b+b=-5 - b+b$ $-13 + 4b=-5$

Step3: Add 13 to both sides

To isolate the term with $b$. $-13+13 + 4b=-5 + 13$ $4b = 8$

Step4: Divide both sides by 4

To solve for $b$. $\frac{4b}{4}=\frac{8}{4}$ $b = 2$

Answer:

$b = 2$