what is the solution of log₂(3x - 7) = 3?\n1/3\n4\n5\n16/3

Answer:

D. $\frac{15}{3}$

Explanation:

Step1: Convert to exponential form

By the definition of logarithms, if $\log_{a}b = c$, then $b=a^{c}$. So for $\log_{2}(3x - 7)=3$, we have $3x-7 = 2^{3}$.

Step2: Calculate the right - hand side

$2^{3}=8$, so the equation becomes $3x - 7=8$.

Step3: Solve for x

Add 7 to both sides: $3x=8 + 7$, so $3x=15$. Then divide both sides by 3, we get $x = 5=\frac{15}{3}$.