what is the solution to $log_{4}8x = 3$?\n$x=\frac{3}{8}$\n$x=\frac{3}{2}$\n$x = 2$\n$x = 8$

Explanation:

Step1: Convert to exponential form

By the definition of logarithms, if $\log_{a}b = c$, then $a^{c}=b$. So for $\log_{4}8x = 3$, we have $4^{3}=8x$.

Step2: Calculate $4^{3}$

$4^{3}=4\times4\times4 = 64$. So the equation becomes $64 = 8x$.

Step3: Solve for $x$

Divide both sides of the equation $64 = 8x$ by 8. We get $x=\frac{64}{8}=8$.

Answer:

$x = 8$