what are the solution(s) to the quadratic equation $x^{2}-25 = 0$?\n$x = 5$ and $x=-5$\n$x = 25$ and…

what are the solution(s) to the quadratic equation $x^{2}-25 = 0$?\n$x = 5$ and $x=-5$\n$x = 25$ and $x=-25$\n$x = 125$ and $x=-125$\nno real solution

what are the solution(s) to the quadratic equation $x^{2}-25 = 0$?\n$x = 5$ and $x=-5$\n$x = 25$ and $x=-25$\n$x = 125$ and $x=-125$\nno real solution

Answer

Explanation:

Step1: Isolate the variable term

Add 25 to both sides of the equation $x^{2}-25 = 0$. We get $x^{2}=25$.

Step2: Take the square - root of both sides

If $x^{2}=25$, then $x=\pm\sqrt{25}$. Since $\sqrt{25} = 5$, $x = 5$ or $x=-5$.

Answer:

A. $x = 5$ and $x=-5$