what are the solution(s) to the quadratic equation 9x² = 4?\no x = 4/9 and x = -4/9\no x = 2/3 and x =…

what are the solution(s) to the quadratic equation 9x² = 4?\no x = 4/9 and x = -4/9\no x = 2/3 and x = -2/3\no x = 3/2 and x = -3/2\no no real solution

what are the solution(s) to the quadratic equation 9x² = 4?\no x = 4/9 and x = -4/9\no x = 2/3 and x = -2/3\no x = 3/2 and x = -3/2\no no real solution

Answer

Explanation:

Step1: Isolate $x^{2}$

Divide both sides of the equation $9x^{2}=4$ by 9. We get $x^{2}=\frac{4}{9}$.

Step2: Solve for $x$

Take the square - root of both sides. Remember that if $x^{2}=a$ ($a\geq0$), then $x = \pm\sqrt{a}$. So $x=\pm\sqrt{\frac{4}{9}}=\pm\frac{2}{3}$.

Answer:

$x = \frac{2}{3}$ and $x=-\frac{2}{3}$