what is the solution of $sqrt{x - 4}+5 = 2$?\n$x=-17$\n$x = 13$\n$x = 53$\nno solution

what is the solution of $sqrt{x - 4}+5 = 2$?\n$x=-17$\n$x = 13$\n$x = 53$\nno solution

what is the solution of $sqrt{x - 4}+5 = 2$?\n$x=-17$\n$x = 13$\n$x = 53$\nno solution

Answer

Explanation:

Step1: Isolate the square - root term

Subtract 5 from both sides of the equation $\sqrt{x - 4}+5 = 2$. $\sqrt{x - 4}=2 - 5=-3$

Step2: Analyze the square - root property

The square root of a number $\sqrt{a}$ (where $a=x - 4$ in our case) is defined such that $\sqrt{a}\geq0$ for all real - valued $a\geq0$. Here, we have $\sqrt{x - 4}=-3$, but the square root of a real number cannot be negative.

Answer:

no solution