what is the solution to this system of linear equations?\n2x + y = 1\n3x - y = -6\n(-1, 3)\n(1, -1)\n(2…
what is the solution to this system of linear equations?\n2x + y = 1\n3x - y = -6\n(-1, 3)\n(1, -1)\n(2, 3)\n(5, 0)
Answer
Explanation:
Step1: Add the two equations
Adding $2x + y = 1$ and $3x - y=-6$ eliminates $y$. $(2x + y)+(3x - y)=1+( - 6)$ $2x+3x+y - y=-5$ $5x=-5$
Step2: Solve for $x$
Divide both sides of $5x = - 5$ by 5. $x=\frac{-5}{5}=-1$
Step3: Substitute $x$ into the first - equation
Substitute $x = - 1$ into $2x + y = 1$. $2\times(-1)+y = 1$ $-2 + y = 1$
Step4: Solve for $y$
Add 2 to both sides of $-2 + y = 1$. $y=1 + 2=3$
Answer:
A. $(-1,3)$