what is the solution to this system of linear equations?\n3x - 2y = 14\n5x + y = 32\n(3, 5)\n(6, 2)\n(8…

Explanation:

Step1: Solve the second - equation for y

From $5x + y=32$, we get $y = 32 - 5x$.

Step2: Substitute y into the first equation

Substitute $y = 32 - 5x$ into $3x-2y = 14$. So $3x-2(32 - 5x)=14$. Expand the left - hand side: $3x-64 + 10x=14$. Combine like terms: $13x-64 = 14$. Add 64 to both sides: $13x=14 + 64$, so $13x=78$. Divide both sides by 13: $x = 6$.

Step3: Find the value of y

Substitute $x = 6$ into $y = 32 - 5x$. Then $y=32-5\times6=32 - 30 = 2$.

Answer:

B. $(6,2)$