what is the solution to this system of linear equations?\n7x - 2y = -6\n8x + y = 3\n(-6, 3)\n(0, 3)\n(1…

Explanation:

Step1: Isolate y in the second - equation

From $8x + y=3$, we get $y = 3 - 8x$.

Step2: Substitute y into the first equation

Substitute $y = 3 - 8x$ into $7x-2y=-6$. Then $7x-2(3 - 8x)=-6$. Expand the left - hand side: $7x-6 + 16x=-6$. Combine like terms: $23x-6=-6$. Add 6 to both sides: $23x=-6 + 6$, so $23x=0$, and $x = 0$.

Step3: Find the value of y

Substitute $x = 0$ into $y = 3 - 8x$. Then $y=3-8\times0=3$.

Answer:

$(0,3)$