which are the solutions of $x^{2}=-13x - 4$?\n0, 13\n0, -13\n$\frac{13-sqrt{153}}{2}$, $\frac{13 +…

which are the solutions of $x^{2}=-13x - 4$?\n0, 13\n0, -13\n$\frac{13-sqrt{153}}{2}$, $\frac{13 + sqrt{153}}{2}$\n$\frac{-13-sqrt{153}}{2}$, $\frac{-13+sqrt{153}}{2}$

which are the solutions of $x^{2}=-13x - 4$?\n0, 13\n0, -13\n$\frac{13-sqrt{153}}{2}$, $\frac{13 + sqrt{153}}{2}$\n$\frac{-13-sqrt{153}}{2}$, $\frac{-13+sqrt{153}}{2}$

Answer

Explanation:

Step1: Rearrange to standard quadratic form

$x^{2}+13x + 4=0$

Step2: Identify coefficients for quadratic formula

For $ax^{2}+bx + c = 0$, here $a = 1$, $b = 13$, $c = 4$.

Step3: Apply quadratic formula $x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

$x=\frac{-13\pm\sqrt{13^{2}-4\times1\times4}}{2\times1}=\frac{-13\pm\sqrt{169 - 16}}{2}=\frac{-13\pm\sqrt{153}}{2}$

Answer:

D. $\frac{-13 - \sqrt{153}}{2},\frac{-13+\sqrt{153}}{2}$