what are the solutions of $x^{2}+6x - 6=10$?\n$x=-11$ or $x = 1$\n$x=-11$ or $x=-1$\n$x=-8$ or…

what are the solutions of $x^{2}+6x - 6=10$?\n$x=-11$ or $x = 1$\n$x=-11$ or $x=-1$\n$x=-8$ or $x=-2$\n$x=-8$ or $x = 2$

what are the solutions of $x^{2}+6x - 6=10$?\n$x=-11$ or $x = 1$\n$x=-11$ or $x=-1$\n$x=-8$ or $x=-2$\n$x=-8$ or $x = 2$

Answer

Explanation:

Step1: Rearrange the equation

First, rewrite $x^{2}+6x - 6=10$ as $x^{2}+6x-16 = 0$.

Step2: Factor the quadratic equation

We need to find two numbers that multiply to - 16 and add up to 6. The numbers are 8 and - 2. So, $x^{2}+6x - 16=(x + 8)(x - 2)=0$.

Step3: Solve for x

Set each factor equal to zero: If $x + 8=0$, then $x=-8$. If $x - 2=0$, then $x = 2$.

Answer:

$x=-8$ or $x = 2$