what are the solutions to $x^{2}+8x + 7 = 0$?\n$x=-8$ and $x=-7$\n$x=-7$ and $x=-1$\n$x = 1$ and $x = 7$\n$x…

what are the solutions to $x^{2}+8x + 7 = 0$?\n$x=-8$ and $x=-7$\n$x=-7$ and $x=-1$\n$x = 1$ and $x = 7$\n$x = 7$ and $x = 8$

what are the solutions to $x^{2}+8x + 7 = 0$?\n$x=-8$ and $x=-7$\n$x=-7$ and $x=-1$\n$x = 1$ and $x = 7$\n$x = 7$ and $x = 8$

Answer

Explanation:

Step1: Factor the quadratic equation

We need to find two numbers that multiply to 7 (the constant term) and add up to 8 (the coefficient of x). The numbers are 7 and 1. So, $x^{2}+8x + 7=(x + 7)(x+1)=0$.

Step2: Solve for x

If $(x + 7)(x + 1)=0$, then by the zero - product property, either $x+7=0$ or $x + 1=0$. For $x+7=0$, we get $x=-7$. For $x + 1=0$, we get $x=-1$.

Answer:

x = -7 and x = -1