what are the solutions to x² + 8x + 7 = 0?\no x = -8 and x = -7\no x = -7 and x = -1\no x = 1 and x = 7\no x…

what are the solutions to x² + 8x + 7 = 0?\no x = -8 and x = -7\no x = -7 and x = -1\no x = 1 and x = 7\no x = 7 and x = 8

what are the solutions to x² + 8x + 7 = 0?\no x = -8 and x = -7\no x = -7 and x = -1\no x = 1 and x = 7\no x = 7 and x = 8

Answer

Explanation:

Step1: Factor the quadratic equation

We need to find two numbers that multiply to 7 (the constant term) and add up to 8 (the coefficient of x). The numbers are 7 and 1. So, $x^{2}+8x + 7=(x + 7)(x+1)=0$.

Step2: Solve for x

If $(x + 7)(x + 1)=0$, then by the zero - product property, either $x+7 = 0$ or $x + 1=0$. If $x+7=0$, then $x=-7$. If $x + 1=0$, then $x=-1$.

Answer:

B. $x=-7$ and $x=-1$