what are the solutions to the equation (2x - 5)(3x - 1) = 0?\no x = -\\frac{5}{2} or x = -\\frac{1}{3}\no x…

what are the solutions to the equation (2x - 5)(3x - 1) = 0?\no x = -\\frac{5}{2} or x = -\\frac{1}{3}\no x = \\frac{2}{5} or x = 3\no x = \\frac{5}{2} or x = \\frac{1}{3}\no x = 5 or x = 1

what are the solutions to the equation (2x - 5)(3x - 1) = 0?\no x = -\\frac{5}{2} or x = -\\frac{1}{3}\no x = \\frac{2}{5} or x = 3\no x = \\frac{5}{2} or x = \\frac{1}{3}\no x = 5 or x = 1

Answer

Explanation:

Step1: Apply zero - product property

If (ab = 0), then (a=0) or (b = 0). Here (a = 2x-5) and (b=3x - 1). So we set up two equations: (2x-5=0) and (3x - 1=0).

Step2: Solve (2x-5 = 0)

Add 5 to both sides: (2x=5). Then divide both sides by 2, we get (x=\frac{5}{2}).

Step3: Solve (3x - 1=0)

Add 1 to both sides: (3x=1). Then divide both sides by 3, we get (x=\frac{1}{3}).

Answer:

C. (x=\frac{5}{2}) or (x=\frac{1}{3})