the solutions to the equation $2x^{2}+x - 1 = 2$ are $x=\frac{-3}{2}$ or $x=square$.

Explanation:

Step1: Rearrange the equation

First, rewrite the equation $2x^{2}+x - 1=2$ as $2x^{2}+x-3 = 0$.

Step2: Factor the quadratic equation

We factor $2x^{2}+x - 3$ into $(2x + 3)(x - 1)=0$.

Step3: Solve for x

Set each factor equal to zero: If $2x+3 = 0$, then $x=-\frac{3}{2}$; if $x - 1=0$, then $x = 1$.

Answer:

$1$