what are the solutions to the equation?\n$x^{2}+6x = 40$\n$x=-10$ and $x = 4$\n$x=-8$ and $x = 5$\n$x=-5$…

what are the solutions to the equation?\n$x^{2}+6x = 40$\n$x=-10$ and $x = 4$\n$x=-8$ and $x = 5$\n$x=-5$ and $x = 8$\n$x=-4$ and $x = 10$

what are the solutions to the equation?\n$x^{2}+6x = 40$\n$x=-10$ and $x = 4$\n$x=-8$ and $x = 5$\n$x=-5$ and $x = 8$\n$x=-4$ and $x = 10$

Answer

Explanation:

Step1: Rearrange to standard form

$x^{2}+6x - 40=0$

Step2: Factor the quadratic

$(x + 10)(x - 4)=0$

Step3: Set each factor to zero

$x+10 = 0$ gives $x=-10$; $x - 4=0$ gives $x = 4$

Answer:

$x=-10$ and $x = 4$