what are the solutions to the quadratic equation $x^2 - 16 = 0$?\n$\\bigcirc$ $x = 2$ and $x =…

what are the solutions to the quadratic equation $x^2 - 16 = 0$?\n$\\bigcirc$ $x = 2$ and $x = -2$\n$\\bigcirc$ $x = 4$ and $x = -4$\n$\\bigcirc$ $x = 8$ and $x = -8$\n$\\bigcirc$ $x = 16$ and $x = -16$

what are the solutions to the quadratic equation $x^2 - 16 = 0$?\n$\\bigcirc$ $x = 2$ and $x = -2$\n$\\bigcirc$ $x = 4$ and $x = -4$\n$\\bigcirc$ $x = 8$ and $x = -8$\n$\\bigcirc$ $x = 16$ and $x = -16$

Answer

Explanation:

Step1: Rearrange the equation

We start with the quadratic equation (x^{2}-16 = 0). First, we can rewrite it as (x^{2}=16) by adding 16 to both sides of the equation.

Step2: Solve for x

To solve for (x), we take the square root of both sides. Remember that if (x^{2}=a) (where (a\geq0)), then (x=\pm\sqrt{a}). So for (x^{2} = 16), we have (x=\pm\sqrt{16}). Since (\sqrt{16} = 4), this means (x = 4) or (x=- 4).

Answer:

B. (x = 4) and (x=-4)