what are the solutions to the quadratic equation 4(x + 2)^2 = 36\nx = -11 and x = 7\nx = -7 and x = 11\nx =…
what are the solutions to the quadratic equation 4(x + 2)^2 = 36\nx = -11 and x = 7\nx = -7 and x = 11\nx = -5 and x = 1\nx = -1 and x = 5
Answer
Explanation:
Step1: Divide both sides by 4
[ \begin{align*} \frac{4(x + 2)^2}{4}&=\frac{36}{4}\ (x + 2)^2&=9 \end{align*} ]
Step2: Take square - root of both sides
[ \begin{align*} x+2&=\pm\sqrt{9}\ x + 2&=\pm3 \end{align*} ]
Step3: Solve for x when (x + 2=3)
[ \begin{align*} x&=3 - 2\ x&=1 \end{align*} ]
Step4: Solve for x when (x + 2=-3)
[ \begin{align*} x&=-3 - 2\ x&=-5 \end{align*} ]
Answer:
C. (x=-5) and (x = 1)