what are the solutions of the quadratic equation 49x² = 9?\no x = 1/9 and x = -1/9\no x = 3/7 and x =…

what are the solutions of the quadratic equation 49x² = 9?\no x = 1/9 and x = -1/9\no x = 3/7 and x = -3/7\no x = 3/4 and x = -3/4\no x = 9/49 and x = -9/49

what are the solutions of the quadratic equation 49x² = 9?\no x = 1/9 and x = -1/9\no x = 3/7 and x = -3/7\no x = 3/4 and x = -3/4\no x = 9/49 and x = -9/49

Answer

Explanation:

Step1: Isolate $x^{2}$

Divide both sides of $49x^{2}=9$ by 49. We get $x^{2}=\frac{9}{49}$.

Step2: Solve for $x$

Take the square - root of both sides. Remember that if $x^{2}=a$ ($a\geq0$), then $x = \pm\sqrt{a}$. So $x=\pm\sqrt{\frac{9}{49}}=\pm\frac{3}{7}$.

Answer:

$x = \frac{3}{7}$ and $x=-\frac{3}{7}$ (the second option)