what are the solutions to the quadratic equation 4x² = 64?\no x = -16 and x = 16\no x = -8 and x = 8\no x =…
what are the solutions to the quadratic equation 4x² = 64?\no x = -16 and x = 16\no x = -8 and x = 8\no x = -4 and x = 4\no x = -2 and x = 2
Answer
Explanation:
Step1: Isolate $x^{2}$
Divide both sides of the equation $4x^{2}=64$ by 4. We get $x^{2}=\frac{64}{4}=16$.
Step2: Solve for $x$
Take the square - root of both sides. Since $x^{2}=16$, then $x = \pm\sqrt{16}$. So $x = 4$ or $x=-4$.
Answer:
$x = - 4$ and $x = 4$