what are the solutions to the quadratic equation 3(x - 4)^2 = 75?\no x = -9 and x = 1\no x = -5 and x = 5\no…
what are the solutions to the quadratic equation 3(x - 4)^2 = 75?\no x = -9 and x = 1\no x = -5 and x = 5\no x = -4 and x = 4\no x = -1 and x = 9
Answer
Explanation:
Step1: Divide both sides by 3
Divide $3(x - 4)^2=75$ by 3, we get $(x - 4)^2 = 25$.
Step2: Take square - root of both sides
$x-4=\pm\sqrt{25}$, so $x - 4=\pm5$.
Step3: Solve for x when $x - 4 = 5$
Add 4 to both sides: $x=5 + 4=9$.
Step4: Solve for x when $x - 4=-5$
Add 4 to both sides: $x=-5 + 4=-1$.
Answer:
D. $x=-1$ and $x = 9$