solve for x.\n6(x - 1) = 9(x + 2)\no x = -8\no x = -3\no x = 3\no x = 8

solve for x.\n6(x - 1) = 9(x + 2)\no x = -8\no x = -3\no x = 3\no x = 8

solve for x.\n6(x - 1) = 9(x + 2)\no x = -8\no x = -3\no x = 3\no x = 8

Answer

Explanation:

Step1: Expand both sides

$6(x - 1)=6x-6$ and $9(x + 2)=9x + 18$, so the equation becomes $6x-6=9x + 18$.

Step2: Move x - terms to one side

Subtract $6x$ from both sides: $6x-6-6x=9x + 18-6x$, which simplifies to $-6 = 3x+18$.

Step3: Move constant terms to one side

Subtract 18 from both sides: $-6-18=3x+18 - 18$, resulting in $-24 = 3x$.

Step4: Solve for x

Divide both sides by 3: $\frac{-24}{3}=\frac{3x}{3}$, so $x=-8$.

Answer:

A. $x = - 8$