solve for n.\n n + 1 = 4(n - 8)\n o n = 1\n o n = 8\n o n = 11\n o n = 16

solve for n.\n n + 1 = 4(n - 8)\n o n = 1\n o n = 8\n o n = 11\n o n = 16
Answer
Explanation:
Step1: Expand the right - hand side
$n + 1=4n-32$
Step2: Move terms with n to one side
$n-4n=-32 - 1$
Step3: Simplify both sides
$-3n=-33$
Step4: Solve for n
$n = 11$
Answer:
$n = 11$