solve for n.\n n + 1 = 4(n - 8)\n n = 1\n n = 8\n n = 11\n n = 16

solve for n.\n n + 1 = 4(n - 8)\n n = 1\n n = 8\n n = 11\n n = 16

solve for n.\n n + 1 = 4(n - 8)\n n = 1\n n = 8\n n = 11\n n = 16

Answer

Answer:

C. $n = 11$

Explanation:

Step1: Expand the right - hand side

$n + 1=4n-32$

Step2: Move terms with $n$ to one side

$1 + 32=4n - n$

Step3: Simplify both sides

$33 = 3n$

Step4: Solve for $n$

$n=\frac{33}{3}=11$