solve for n.\n n + 1 = 4(n - 8)\n n = 1\n n = 8\n n = 11\n n = 16

solve for n.\n n + 1 = 4(n - 8)\n n = 1\n n = 8\n n = 11\n n = 16
Answer
Answer:
C. $n = 11$
Explanation:
Step1: Expand the right - hand side
$n + 1=4n-32$
Step2: Move terms with $n$ to one side
$1 + 32=4n - n$
Step3: Simplify both sides
$33 = 3n$
Step4: Solve for $n$
$n=\frac{33}{3}=11$