solve for n.\n11(n - 1) + 35 = 3n\no n = -6\no n = -3\no n = 3\no n = 6

solve for n.\n11(n - 1) + 35 = 3n\no n = -6\no n = -3\no n = 3\no n = 6

solve for n.\n11(n - 1) + 35 = 3n\no n = -6\no n = -3\no n = 3\no n = 6

Answer

Answer:

n = -3

Explanation:

Step1: Expand the left - hand side

$11(n - 1)+35=11n-11 + 35=11n+24$ So the equation becomes $11n + 24=3n$.

Step2: Move terms with n to one side

Subtract $3n$ from both sides: $11n-3n + 24=3n-3n$, which simplifies to $8n+24 = 0$.

Step3: Isolate the term with n

Subtract 24 from both sides: $8n+24 - 24=0 - 24$, getting $8n=-24$.

Step4: Solve for n

Divide both sides by 8: $n=\frac{-24}{8}=-3$.