solve for d.\nd² + 11 = 4\nwrite your answer in simplified, rationalized form.\nd = or d =

Explanation:

Step1: Isolate the square - term

Subtract 11 from both sides of the equation $d^{2}+11 = 4$. $d^{2}=4 - 11$ $d^{2}=-7$

Step2: Solve for d

Take the square - root of both sides. Remember that $\sqrt{-a}=i\sqrt{a}$ for $a>0$. $d=\pm\sqrt{-7}=\pm i\sqrt{7}$

Answer:

$d = i\sqrt{7}$ or $d=-i\sqrt{7}$