solve for k.\n-12 = -4(k - 13)\nk =
solve for k.\n-12 = -4(k - 13)\nk =
Answer
Explanation:
Step1: Divide both sides by -4
$$\frac{-12}{-4}=\frac{-4(k - 13)}{-4}$$ $$3=k - 13$$
Step2: Add 13 to both sides
$$3+13=k - 13+13$$ $$16=k$$
Answer:
(16)
solve for k.\n-12 = -4(k - 13)\nk =
$$\frac{-12}{-4}=\frac{-4(k - 13)}{-4}$$ $$3=k - 13$$
$$3+13=k - 13+13$$ $$16=k$$
(16)