solve for t.\n12 = 3(t + 2)\nt =
solve for t.\n12 = 3(t + 2)\nt =
Answer
Explanation:
Step1: Divide both sides by 3
$$\frac{12}{3}=\frac{3(t + 2)}{3}$$ $$4=t + 2$$
Step2: Subtract 2 from both sides
$$4-2=t+2 - 2$$
Answer:
$2$
solve for t.\n12 = 3(t + 2)\nt =
$$\frac{12}{3}=\frac{3(t + 2)}{3}$$ $$4=t + 2$$
$$4-2=t+2 - 2$$
$2$