solve for c.\n-15 - 2(14 + c) = -3\nc =

solve for c.\n-15 - 2(14 + c) = -3\nc =

solve for c.\n-15 - 2(14 + c) = -3\nc =

Answer

Explanation:

Step1: Expand the equation

$$ \begin{align*} -15-2(14 + c)&=-3\ -15-(2\times14+2\times c)&=-3\ -15-(28 + 2c)&=-3\ -15-28-2c&=-3\ -43-2c&=-3 \end{align*} $$

Step2: Isolate the term with (c)

Add (43) to both sides of the equation: $$ \begin{align*} -43-2c + 43&=-3+ 43\ -2c&=40 \end{align*} $$

Step3: Solve for (c)

Divide both sides by (-2): $$ \begin{align*} \frac{-2c}{-2}&=\frac{40}{-2}\ c&=-20 \end{align*} $$

Answer:

(c = -20)