solve: 24 < 4x - 3 + 5x + 6\na x > 3\nb x > \\frac{7}{3}\nc x < \\frac{7}{3}\nd x < 3

solve: 24 < 4x - 3 + 5x + 6\na x > 3\nb x > \\frac{7}{3}\nc x < \\frac{7}{3}\nd x < 3
Answer
Answer:
A. (x > 3)

solve: 24 < 4x - 3 + 5x + 6\na x > 3\nb x > \\frac{7}{3}\nc x < \\frac{7}{3}\nd x < 3
A. (x > 3)