solve: 4(2a + 3) < 3(a - 1)

Answer:

B. a < -3

Explanation:

Step1: Expand both sides

$4(2a + 3)=8a+12$ and $3(a - 1)=3a-3$. So the inequality becomes $8a + 12<3a - 3$.

Step2: Move terms with a to one - side

Subtract $3a$ from both sides: $8a-3a + 12<3a-3a - 3$, which simplifies to $5a+12<-3$.

Step3: Move the constant to the other side

Subtract 12 from both sides: $5a+12 - 12<-3 - 12$, getting $5a<-15$.

Step4: Solve for a

Divide both sides by 5: $\frac{5a}{5}<\frac{-15}{5}$, so $a < - 3$.