solve $2x^2 + x - 4 = 0$.\n$x^2 + \\square x + \\square = 0$

solve $2x^2 + x - 4 = 0$.\n$x^2 + \\square x + \\square = 0$

solve $2x^2 + x - 4 = 0$.\n$x^2 + \\square x + \\square = 0$

Answer

Explanation:

Step1: Divide the equation by 2

To make the coefficient of (x^2) equal to 1, we divide each term of the equation (2x^{2}+x - 4=0) by 2. (\frac{2x^{2}}{2}+\frac{x}{2}-\frac{4}{2}=\frac{0}{2})

Step2: Simplify each term

Simplifying the left - hand side and the right - hand side of the equation: (x^{2}+\frac{1}{2}x - 2=0)

Answer:

The first blank is (\frac{1}{2}) and the second blank is (- 2)