solve for z.\n42 = -7(z - 3)\nz =
solve for z.\n42 = -7(z - 3)\nz =
Answer
Explanation:
Step1: Divide both sides by -7
$$\frac{42}{-7}=\frac{-7(z - 3)}{-7}$$ $$-6=z - 3$$
Step2: Add 3 to both sides
$$-6+3=z-3 + 3$$ $$z=-3$$
Answer:
(z=-3)
solve for z.\n42 = -7(z - 3)\nz =
$$\frac{42}{-7}=\frac{-7(z - 3)}{-7}$$ $$-6=z - 3$$
$$-6+3=z-3 + 3$$ $$z=-3$$
(z=-3)