to solve $49^{3x}=343^{2x + 1}$, write each side of the equation in terms of base

to solve $49^{3x}=343^{2x + 1}$, write each side of the equation in terms of base

to solve $49^{3x}=343^{2x + 1}$, write each side of the equation in terms of base

Answer

Explanation:

Step1: Analyze the numbers

We know that (49 = 7^2) and (343=7^3).

Step2: Rewrite the equation

The left - hand side (49^{3x}=(7^2)^{3x}), and the right - hand side (343^{2x + 1}=(7^3)^{2x+1}).

Answer:

7