to solve 49^{3x}=343^{2x + 1}, write each side of the equation in terms of base 7. complete choose the…

to solve 49^{3x}=343^{2x + 1}, write each side of the equation in terms of base 7. complete choose the correct equation. (7)^{3x}=(7^{3})^{2x + 1} (7^{2})^{3x}=(7^{3})^{2x + 1} (7^{2})^{3x}=(7^{4})^{2x + 1} done

to solve 49^{3x}=343^{2x + 1}, write each side of the equation in terms of base 7. complete choose the correct equation. (7)^{3x}=(7^{3})^{2x + 1} (7^{2})^{3x}=(7^{3})^{2x + 1} (7^{2})^{3x}=(7^{4})^{2x + 1} done

Answer

Explanation:

Step1: Rewrite 49 in base - 7

Since (49 = 7^2), then (49^{3x}=(7^2)^{3x}).

Step2: Rewrite 343 in base - 7

Since (343 = 7^3), then (343^{2x + 1}=(7^3)^{2x+1}).

Answer:

((7^2)^{3x}=(7^3)^{2x + 1}) (the second option)