solve for f.\n6 + 4f = 6(2f + 7) + 10f\nf =

solve for f.\n6 + 4f = 6(2f + 7) + 10f\nf =

solve for f.\n6 + 4f = 6(2f + 7) + 10f\nf =

Answer

Explanation:

Step1: Expand the right - hand side

$$6(2f + 7)=12f+42$$ The equation becomes $6 + 4f=12f + 42+10f$.

Step2: Combine like terms on the right - hand side

$12f+10f = 22f$. So the equation is $6 + 4f=22f + 42$.

Step3: Move the terms with (f) to one side and constants to the other side

Subtract (4f) from both sides: $6=22f + 42-4f$. Subtract (42) from both sides: $6 - 42=22f-4f$.

Step4: Simplify both sides

$6-42=-36$ and $22f - 4f = 18f$. So, $-36 = 18f$.

Step5: Solve for (f)

Divide both sides by (18): $f=\frac{-36}{18}$.

Answer:

(f=-2)