solve for b.\n3 - 2(b - 2) = 2 - 7b\nb =

solve for b.\n3 - 2(b - 2) = 2 - 7b\nb =

solve for b.\n3 - 2(b - 2) = 2 - 7b\nb =

Answer

Explanation:

Step1: Expand the left - hand side

$3-2(b - 2)=3-2b + 4=7-2b$ So the equation becomes $7-2b=2-7b$.

Step2: Move the terms with $b$ to one side

Add $7b$ to both sides: $7-2b + 7b=2-7b+7b$, which simplifies to $7 + 5b=2$.

Step3: Move the constant term to the other side

Subtract 7 from both sides: $7 + 5b-7=2-7$, getting $5b=-5$.

Step4: Solve for $b$

Divide both sides by 5: $b=\frac{-5}{5}=-1$.

Answer:

$-1$