solve for c.\n9 - 2(9c + 1) = -9c - 6c - 5\nc =

solve for c.\n9 - 2(9c + 1) = -9c - 6c - 5\nc =

solve for c.\n9 - 2(9c + 1) = -9c - 6c - 5\nc =

Answer

Explanation:

Step1: Expand the left - hand side

Use the distributive property (a(b + c)=ab+ac). (9-2(9c + 1)=9-(18c + 2)=9-18c-2=7-18c) The right - hand side: (-9c-6c - 5=-15c-5) So the equation becomes (7-18c=-15c-5)

Step2: Move the terms with (c) to one side

Add (18c) to both sides of the equation: (7-18c + 18c=-15c-5 + 18c) (7 = 3c-5)

Step3: Solve for (c)

Add (5) to both sides: (7 + 5=3c-5 + 5), which gives (12 = 3c) Divide both sides by (3): (c=\frac{12}{3})

Answer:

(4)