solve for x in the equation $x^{2}+10x + 12=36$.\n$x=-12$ or $x = 2$\n$x=-11$ or $x = 1$\n$x=-2$ or $x =…

solve for x in the equation $x^{2}+10x + 12=36$.\n$x=-12$ or $x = 2$\n$x=-11$ or $x = 1$\n$x=-2$ or $x = 12$\n$x=-1$ or $x = 11$

solve for x in the equation $x^{2}+10x + 12=36$.\n$x=-12$ or $x = 2$\n$x=-11$ or $x = 1$\n$x=-2$ or $x = 12$\n$x=-1$ or $x = 11$

Answer

Explanation:

Step1: Rearrange to standard quadratic form

$x^{2}+10x + 12-36=0$, so $x^{2}+10x - 24 = 0$.

Step2: Factor the quadratic equation

We need two numbers that multiply to - 24 and add up to 10. The numbers are 12 and - 2. So $(x + 12)(x - 2)=0$.

Step3: Solve for x

If $(x + 12)(x - 2)=0$, then $x+12 = 0$ or $x - 2=0$. Solving $x+12 = 0$ gives $x=-12$, and solving $x - 2=0$ gives $x = 2$.

Answer:

A. $x=-12$ or $x = 2$