solve the following absolute value inequality.\n$\frac{|x + 8|}{7}geq1$\n$xgeq$\n$xleq$
solve the following absolute value inequality.\n$\frac{|x + 8|}{7}geq1$\n$xgeq$\n$xleq$
Answer
Explanation:
Step1: Multiply both sides by 7
$|x + 8|\geq7$
Step2: Consider two - cases
Case 1: $x+8\geq7$. Solving for $x$ gives $x\geq7 - 8$, so $x\geq - 1$. Case 2: $x + 8\leq - 7$. Solving for $x$ gives $x\leq-7 - 8$, so $x\leq - 15$.
Answer:
$x\geq - 1$; $x\leq - 15$