solve: $-\\frac{2}{5}(n + 2)=6$\na $n=-13$\nb $n=-10$\nc $n=17$\nd $n=-17$

solve: $-\\frac{2}{5}(n + 2)=6$\na $n=-13$\nb $n=-10$\nc $n=17$\nd $n=-17$

solve: $-\\frac{2}{5}(n + 2)=6$\na $n=-13$\nb $n=-10$\nc $n=17$\nd $n=-17$

Answer

Answer:

D. $n = - 17$

Explanation:

Step1: Eliminate the coefficient

Multiply both sides by $-\frac{5}{2}$. $-\frac{5}{2}\times(-\frac{2}{5})(n + 2)=6\times(-\frac{5}{2})$ $n + 2=-15$

Step2: Solve for $n$

Subtract 2 from both sides. $n=-15 - 2$ $n=-17$