solve for d.\n3 = \\frac{d}{5} - 1\nd =
solve for d.\n3 = \\frac{d}{5} - 1\nd =
Answer
Explanation:
Step1: Add 1 to both sides
$$3 + 1=\frac{d}{5}-1 + 1$$ $$4=\frac{d}{5}$$
Step2: Multiply both sides by 5
$$4\times5=\frac{d}{5}\times5$$
Answer:
20
solve for d.\n3 = \\frac{d}{5} - 1\nd =
$$3 + 1=\frac{d}{5}-1 + 1$$ $$4=\frac{d}{5}$$
$$4\times5=\frac{d}{5}\times5$$
20