solve for j.\n-2 + \\frac{3}{4}j + \\frac{1}{2}j = 2j\nj =

solve for j.\n-2 + \\frac{3}{4}j + \\frac{1}{2}j = 2j\nj =

solve for j.\n-2 + \\frac{3}{4}j + \\frac{1}{2}j = 2j\nj =

Answer

Explanation:

Step1: Combine like terms

Combine the terms with (j) on the left - hand side: (\frac{3}{4}j+\frac{1}{2}j=\frac{3}{4}j+\frac{2}{4}j=\frac{3 + 2}{4}j=\frac{5}{4}j). The equation becomes (-2+\frac{5}{4}j = 2j).

Step2: Move terms with (j) to one side

Subtract (\frac{5}{4}j) from both sides: (-2=2j-\frac{5}{4}j). Then, (2j-\frac{5}{4}j=\frac{8}{4}j-\frac{5}{4}j=\frac{8 - 5}{4}j=\frac{3}{4}j). So, (-2=\frac{3}{4}j).

Step3: Solve for (j)

Multiply both sides by (\frac{4}{3}): (j=-2\times\frac{4}{3}=-\frac{8}{3}).

Answer:

(j =-\frac{8}{3})