solve $\frac{1}{2}+\frac{1}{2x}=\frac{x^{2}-7x + 10}{4x}$ by rewriting the equation as a proportion. which…

solve $\frac{1}{2}+\frac{1}{2x}=\frac{x^{2}-7x + 10}{4x}$ by rewriting the equation as a proportion. which proportion is equivalent to the original equation? $\frac{x + 2}{2x}=\frac{x^{2}-7x + 10}{4x}$ $\frac{x - 1}{2x}=\frac{x^{2}-7x + 10}{4x}$ $\frac{x + 1}{2x}=\frac{x^{2}-7x + 10}{4x}$

solve $\frac{1}{2}+\frac{1}{2x}=\frac{x^{2}-7x + 10}{4x}$ by rewriting the equation as a proportion. which proportion is equivalent to the original equation? $\frac{x + 2}{2x}=\frac{x^{2}-7x + 10}{4x}$ $\frac{x - 1}{2x}=\frac{x^{2}-7x + 10}{4x}$ $\frac{x + 1}{2x}=\frac{x^{2}-7x + 10}{4x}$

Answer

Explanation:

Step1: Find a common - denominator for the left - hand side

The common denominator of 2 and 2x is 2x. Rewrite $\frac{1}{2}$ as $\frac{x}{2x}$. Then $\frac{1}{2}+\frac{1}{2x}=\frac{x}{2x}+\frac{1}{2x}=\frac{x + 1}{2x}$.

Answer:

C. $\frac{x + 1}{2x}=\frac{x^{2}-7x + 10}{4x}$