solve for f.\n2 - \\frac{1}{4}f = f - \\frac{3}{4}f + 3\nf =

Explanation:

Step1: Simplify right - hand side

Combine like terms on the right - hand side: $f-\frac{3}{4}f=\frac{4f - 3f}{4}=\frac{1}{4}f$. So the equation becomes $2-\frac{1}{4}f=\frac{1}{4}f + 3$.

Step2: Move terms with $f$ to one side

Add $\frac{1}{4}f$ to both sides: $2-\frac{1}{4}f+\frac{1}{4}f=\frac{1}{4}f+\frac{1}{4}f + 3$, which simplifies to $2=\frac{1 + 1}{4}f+3$, or $2=\frac{1}{2}f+3$.

Step3: Isolate the term with $f$

Subtract 3 from both sides: $2 - 3=\frac{1}{2}f+3 - 3$, getting $-1=\frac{1}{2}f$.

Step4: Solve for $f$

Multiply both sides by 2: $-1\times2=\frac{1}{2}f\times2$. So $f=-2$.

Answer:

$-2$