solve for x.\n2 + \\frac{3}{4}x = x - \\frac{3}{4}\nx =

solve for x.\n2 + \\frac{3}{4}x = x - \\frac{3}{4}\nx =

solve for x.\n2 + \\frac{3}{4}x = x - \\frac{3}{4}\nx =

Answer

Explanation:

Step1: Move terms with x to one side

$$2+\frac{3}{4}x - x=-\frac{3}{4}$$ $$2-\frac{1}{4}x = -\frac{3}{4}$$

Step2: Move constant terms to the other side

$$-\frac{1}{4}x=-\frac{3}{4}-2$$ $$-\frac{1}{4}x=-\frac{3}{4}-\frac{8}{4}$$ $$-\frac{1}{4}x = -\frac{11}{4}$$

Step3: Solve for x

Multiply both sides by - 4: $$x = 11$$

Answer:

(11)