solve for v.\n\frac{1}{2}v + 8 = 3-\frac{1}{3}v\nv = square

Explanation:

Step1: Combine like - terms

Add $\frac{1}{3}v$ to both sides of the equation: $\frac{1}{2}v+\frac{1}{3}v + 8=3-\frac{1}{3}v+\frac{1}{3}v$. $\left(\frac{1}{2}+\frac{1}{3}\right)v + 8=3$. Find a common denominator for the $v$ terms: $\frac{3 + 2}{6}v+8 = 3$, so $\frac{5}{6}v+8 = 3$.

Step2: Isolate the term with $v$

Subtract 8 from both sides: $\frac{5}{6}v+8 - 8=3 - 8$. $\frac{5}{6}v=-5$.

Step3: Solve for $v$

Multiply both sides by $\frac{6}{5}$: $v=-5\times\frac{6}{5}$. $v=-6$.

Answer:

$-6$