solve for d.\n$\frac{4}{5}d + 3=-2-\frac{1}{5}d$\n$d = square$

Explanation:

Step1: Combine like - terms

Add $\frac{1}{5}d$ to both sides of the equation: $\frac{4}{5}d+\frac{1}{5}d + 3=-2-\frac{1}{5}d+\frac{1}{5}d$ $(\frac{4 + 1}{5})d+3=-2$ $d + 3=-2$

Step2: Isolate the variable $d$

Subtract 3 from both sides of the equation: $d+3 - 3=-2 - 3$ $d=-5$

Answer:

$-5$